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Now that you've got the idea, can you generalise to create a polygon(n) function that will draw a polygon of default side 100?
Have a go before clicking here to reveal my pentagon.

function polygon(n,d=100) {
var angle=360/n;
for (var i=0; i<n; i++) { fd(d); rt(angle);}
}
function test() {
polygon(5);
}
Getting tricky now!

Can you reproduce this pattern using the pentagon? Click here to reveal my answer.

function test() {
for (var i=0;i<10;i++) {
polygon(5,200); rt(36)
}
}
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